source : yahoo.com

## How are newtons per coulomb (N C−1) or, equivalently, volts per meter (V m−1) equivalent?

♠ the matter is that science of electricity and electrical engineering started independent development from different points;

♣ work done by electric current w=I*U*t N·m;

according to science of electricity current is

rate of charge transfer I=Q/t, hence w=Q*U;

without giving up traditional unit Volt for measuring electric potentials we had to introduce a charge unit

Coulomb = N·m/V;

♦ now Coulomb’s law should look: F=k*q*Q/r^2;

on LHS we have Newtons,

on RHS we have (C/m)^2 =(N/V)^2;

to reconcile this contradiction a constant

ε=8.854·10^(-12) N/V^2 was introduced,

ε was named as dielectric constant for void;

so that Coulomb’s law now looks:

F= q*Q/(4π·ε·r^2), giving Newtons on both sides;

♥ E= F/q = Q/(4π·ε·r^2) has units N/C;

N/C = N/(N·m/V) =V/m;

Thus if you say E = 10 N/C

and I say E=10 V/m we are both right;

Coulombs Per Second to Amperes | Kyle's Converter – Coulombs Per Second Conversion Charts. Many Other Conversions. A coulomb per second is the definition of amperes. Ampere is the SI base unit of electric current.Coulomb's law, otherwise known as Coulomb's inverse-square law, describes the electrostatic force acting between two charges. The force acts along the shortest line that joins the charges.Kilovolt Per Centimeter Volt Per Meter Volt Per Centimeter Volt Per Mil Volt Per Inch Kilovolt Per Simple online unit conversion tool to convert volt/centimeter (V/cm) into newton/coulomb (N/C).

Coulomb's Law Calculator – Coulombs law is similar to Newtons law of Gravitation in that each force has an inverse square relation with the Convert this to kilograms, then multiply with the gravity (9.82 meters per square second).If one Coulomb per second moves past a fixed point in a wire, that wire is carrying a current of one Ampere. Conductors allow charge to move freely through them. Metals are good conductors.Coulomb's law states that the electrical force between two charged objects is directly proportional to the product of the quantity of charge on the objects and inversely proportional to the square of the…

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