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## Need help with Writing expression for Kinetic energy!!!?

a)

The point of this problem is that energy is conserved since friction is being neglected. This means that the sum of the potential and kinetic energy of the car is constant along every point on the track. The problem states that the car is at rest to start, so the kinetic energy there (KE0) is 0. The potential energy in reference to the ground at any point is mgx where x is the height above the ground.

To find the kinetic energy at the top of the loop, use your knowledge of the loop height and starting point height to find the difference in potential energy. Since energy is conserved, the kinetic energy will be the difference.

b)

For the car to stay in contact with the entire track, the velocity at the top of the loop must be great enough so that the centrifugal force (m * (v^2) / R) is equal and opposite to the force due to gravity (m*g). By equating these two forces you can get an expression for the minimum velocity at that point. Then do the same thing as in a and equate the sums of the potential and kinetic energies at the top of the loop and at the starting point.

Solved: A-Find An Expression For The Kinetic Energy Of The… – Express In Terms Of M,g,h, And R. B- Find The Minimum Initial Height H At Which The Car Can Be Released That Still Allows The Car To Stay In Contact B- find the minimum initial height h at which the car can be released that still allows the car to stay in contact with the track at the top of the loop.Kinetic Energy: The energy possessed by an object due to its motion is called as kinetic Energy. Let a Force , F acts on the object and let the object from rest moves from point A to point B and covers a ask questions about your assignment. get answers with explanations. find similar questions.We know that at the top of the loop, the velocity must be such that the centripetal acceleration is equal to "g", so g = v2/r, so v2 = gr. Since the formula for kinetic energy uses v2, I will not take the square root.

Derive an expression for kinetic energy possessed by an object of… – Calculate the unknown variable in the equation for kinetic energy, where kinetic energy is equal to one half times the mass multiplied by velocity squared This calculator will find the missing variable in the physics equation for Kinetic Energy of a rigid body, when two of the variables are known.Loop the Loop. A roller coaster car may be approximated by a block of mass m. The car, which starts from rest, is released at a height h above the ground and slides along a frictionless track. Part A Find an expression for the kinetic energy of the car at the top of the loop.The work done by the force will become converted into increased kinetic energy in the body. We derive the expression for kinetic energy from these basic principles. Steps. Method 1 of 2 Otherwise, we would have to find a way to cancel the time variable that would be introduced.

Practice 2A – Express the kinetic energy in terms of , , , and . Use Newton's 2nd law to find an expression for , the magnitude of the normal force that the loop exerts on the car when the car is at the top of the loop.. The kinetic energy of the package increases, indicating that the net work done on the system is positive. This expression is called the work-energy theorem, and it actually applies in general (even for forces that vary in direction and magnitude), although we have derived it for the special case of a…the ratio of the kinetic energy of an object of mass 3m moving at speed 2v to an object of mass m/2 moving at speed v. 2 blocks of masses 1.0 kg and 2.0 kg are pushed by a constant applied force F across a horizontal frictionless table with a constant acc such that the blocks remain in contact w each…