# Solve P=2l+2w&rut=0f5ec366d29e4826e132802d193be7574eefb291ae416d001883215a59257a66 | Microsoft Math Solver

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## Solve P=2l+2w&rut=0f5ec366d29e4826e132802d193be7574eefb291ae416d001883215a59257a66 | Microsoft Math Solver

A pawn broker buys a TV set and a computer for 600. He sells the Computer at a markup of 30% and the

Let the cost of the TV be x and that of the computer be y, thenx + y = 600 . . . . . . . (1)0.2x + 0.3y = 165 . . (2)From (1), x = 600 – y . . . (3)Putting (3) into (2) gives:0.2(600 – y) + 0.3y = …

Let the cost of the TV be x and that of the computer be y, thenx + y = 600 . . . . . . . (1)0.2x + 0.3y = 165 . . (2)From (1), x = 600 – y . . . (3)Putting (3) into (2) gives:0.2(600 – y) + 0.3y = …

Solving Literal Equations – Tutorial – P = 2L + 2W for W. Solution to Example 1. Given P = 2L + 2W we first isolate the term containing W : add -2L to both sides of the equation P – 2L = 2L + 2W – 2L Simplify to obtain P – 2L = 2W Divide both sides by 2 to obtain W. W = (P- 2L) / 2 Example 2 Solve the literal equation H = √ ( x 2 + y 2)You can put this solution on YOUR website! I need to solve for L p=2L+2w Or 2L + 2W = P: Subtract 2W from both sides and you have: 2L = P – 2W: Divide both sides by 2 L = (P-2W)/2 or L = P/2 – WSimplifying p = 2l + 2w Solving p = 2l + 2w Solving for variable 'p'. Move all terms containing p to the left, all other terms to the right. Simplifying p = 2l + 2w You can always share this solution

SOLUTION: I need to solve for L p=2L+2w – The equation is P=2L+2W and you need to solve for L. The first thing that must come in mind is to isolate the L so first start by subtracting 2W on both sides: P – 2W = 2L + 2W – 2W and the +-2Ws…If P = 2l + 2w, the formula to find w is. If P is 30 units and l is 10 units, w is units.P = 2l + 2w Subtracting 2l from each side, we get P – 2l = 2w Dividing each side by 2, we get: P – 2l: 2 = 2w: 2: w = P – 2l : 2: w = 50 – 2(3) 2: w = 50 – 6 : 2: w = 44 : 2: w = 22 Calculate Area (A): The equation for the Area (A) of a rectangle is denoted below: A = l x w where l = length and w = width

p=2l+2w – Get Easy Solution – The perimeter of a rectangle can be found using the equation P = 2L + 2W, where P is the perimeter, L is the length, and W is the width of the rectangle. Can the perimeter of the rectangle be 60 units when its width is 11 units and its length is 24 units?Solve the Literal Equation P = 2L + 2W for LIf you enjoyed this video please consider liking, sharing, and subscribing.Udemy Courses Via My Website: https://…p = 2l + 2w. first remove the added term 2w by subtracting 2w from both sides: p – 2w = 2l + 2w – 2w p – 2w = 2l. now remove the 2 from the 2l by dividing both sides by 2: ( p – 2w ) / 2 = 2l / 2 p / 2 – w = l. So l is p / 2 – w. That's how you solve one of these equations for any particular variable you want. Hope this helps, Stephen La Rocque.