# What Is The Free-fall Acceleration At The Surface Of The Moon? What Is The Free-fall Acceleration At The Surfa?

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## What is the free-fall acceleration at the surface of the moon? What is the free-fall acceleration at the surfa?

F=GMm/r^2, the place G is the gravitational consistent, M is the mass of the earth, m is the mass of the physique, and r is the area between them. g=F/m, the place g is the acceleration using gravity close to the earth’s floor. as a result g=GM/r^2. observe that the mass of the freely falling physique isn’t in this equation; as a result, the acceleration using gravity on earth’s floor does no longer count on the mass of the falling physique.

SOLVED:The free-fall acceleration on the surface – The free-fall acceleration on the surface of the Moon is about one-sixth tha… 03:21 The acceleration due to gravity on the Moon's surface is known to be ab…A)What is the free-fall acceleration at the surface of the moon? B)What is the free-fall acceleration at the surface of the Jupiter?g_("moon")=1.62" " m/s^2 g_("Jupiter")=24.79" "m/s^2 "let us assume that there is an object with a mass of 'm' on the" "moon. The moon will attract this object."

A)What is the free-fall acceleration at the surface of the – "On the Moon, the free-fall acceleration is 1.6 m/s 2." 1.6 m/s 2 "Moon." World Book Encyclopedia Online Reference Center. World Book, 2004. "Because the moon has less mass than Earth, the force due to gravity at the lunar surface is only about 1/6 of that on Earth." 1.6 m/s 2: Astronomy (The Moon). Johnson Space Center. NASA.the value of g is 9.8 meters per square second (32.2 feet per square second) on the surface of the Earth, and has different values on the surface of the Moon and Mars. The gravitational acceleration g decreases with the square of the distance from the center of the planet.Favorite Answer on the moon about 1/6 of earth or 9.81/6 = 1.64 m/s/s on jupiter it is so much harder to say because the level of the surface is unknown for certain. The gravity is so strong that…

What is the free-fall acceleration at the surface of (a – The free-fall acceleration on the surface of the Moon i about one sixth of that on the surface of the Earth. If the radius of the Moon is about 0.250 R E, find the ratio of thei average densities, ρ Moon / ρ Farth.Calculate the mass of the Moon if the free fall acceleration near its surface is known as 1.62 m/s{eq}^2 {/eq} and radius of the moon is 1738km.A newly discovered planet has twice the mass and three times the radius of the earth. What is the free-fall acceleration at its surface, in terms of the free-fall acceleration g at the surface of the earth? Any help is appreciated, Thanks in advance!!

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