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## What is the magnitude of the current in the loop?

The required equation here is derived from calculus using the Biot-Savart Law and iirc the equation for the current will be

I = B*π*L*W / (2μo*sqrt(L^2+W^2))

L=0.095m

W=0.042m

μo=4π*10^-7

so I = 4.3*10^-5*0.095*0.042 / (8*10^-7*sqrt(0.095^2 + 0.042^2)

( π cancels!)

I = 2.06 A

(If that’s not right, maybe the “2” in my original equation should have been in the numerator, which would make the answer 4 times greater???)

Magnetic Field of a Current Loop – The current used in the calculation above is the total current, so for a coil of N turns, the current used is Ni where i is the current supplied to the coil. The Earth's magnetic field at the surface is about 0.5 Gauss. Discussion of current loop: Index Magnetic field concepts Currents as magnetic sourcesTwo loops of wire carry the same current of 10 mA, but flow in opposite directions as seen in Figure 12.13. One loop is measured to have a radius of R = 50cm while the other loop has a radius of 2R = 100cm.The loop is in a constant uniform magnetic field of magnitude 1.00 T, which is oriented perpendicular to the plane of the loop. Assume that you are facing the loop and that the magnetic field points into the loop.

12.4 Magnetic Field of a Current Loop – University Physics – current be a negative number. A loop of wire is horizontal. A bar magnet is pushed toward the loop from below, along the axis of the loop. a. What is the current direction in the loop as the magnet is approaching? Explain. b. Is there a magnetic force on the loop? If so, in which direction? Explain. Hint: A current loop is a magnetic dipole.A loop of radius r = 4.3 cm is placed parallel to the xy-plane in a uniform magnetic field of strength B = 0.51 T in the +z-direction. The resistance of theFind the current through a loop needed to create a maximum torque of 9.00 N. The loop has 50 square turns that are 15.0 cm on a side and is in a uniform 0.800-T magnetic field. 4. Calculate the magnetic field strength needed on a 200-turn square loop 20.0 cm on a side to create a maximum torque of 300 N ⋅ m if the loop is carrying 25.0 A.

Chapter 29: Mastering Physics Flashcards | Quizlet – The magnitude of the magnetic field at the center of the loop is 4.578 x 10⁻⁵ T Explanation: Given; number of turns of the circular loop, n = 15 turns radius of the loop, R = 10.5 cm current flowing in the wire, I = 0.51 A. Magnetic flux, at the center of the loop is given as;A rectangular conducting loop of dimensions l×w and resistance R rests in the plane of a long straight wire as shown. The closest edge of the loop is a distance a from the wire. The current in the wire is in the upward direction and increases at a constant rate from I to 3I in time Δt. Find the magnitude of the induced current in the loop.The induced current always wants to oppose the change in flux, so w hen B is increasing, the circular loop will want to induce a current so that the current creates a B field against the increasing B -field. Thus, the in duced current will be Clockwise. (b) Determine the direction of the induced current in the loop when B is constant with value